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Find the value of the x or y passing through the points with the following points (-2,8)(x,4) m =4/5. (7,5) (1,y) m= -2/3

Find the value of the x or y passing through the points with the following points (-2,8)(x,4) m =4/5. (7,5) (1,y) m= -2/3
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find the value of the x or y passing through the points with the following points (-2,8)(x,4) m =4/5. (7,5) (1,y) m= -2/3

User Anubhav Grover
by
7.7k points

1 Answer

4 votes

\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -2 &,& 8~) % (c,d) &&(~ x &,& 4~) \end{array} \\\\\\ % slope = m slope \implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-8}{x-(-2)}\implies \cfrac{4-8}{x+2}=\stackrel{given~\underline{m}}{\cfrac{4}{5}} \\\\\\ \cfrac{-4}{x+2}=\cfrac{4}{5}\implies -20=(x+2)4\implies -20=4x+8 \\\\\\ -28=4x\implies \cfrac{-28}{4}=x\implies -7=x

now, as far as the second one,


\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~7 &,& 5~) % (c,d) &&(~ 1 &,& y~) \end{array} \\\\\\ % slope = m slope\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-5}{1-7}=\stackrel{given~\underline{m}}{-\cfrac{2}{3}}\implies \cfrac{y-5}{-6}=\cfrac{-2}{3} \\\\\\ 3(y-5)=12\implies 3y-15=12\implies 3y=27 \\\\\\ y=\cfrac{27}{3}\implies y=9
User Mareoraft
by
8.6k points
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