Question

A paperboy rode his bike at 3 m/s. After being chased by a dog for 8 seconds, he was traveling 6m/s. What is his acceleration? Your answer

Answer 1

a=vf-vi/tf-ti
a= velocity final-velocity initial / time final-time initial
a= 6 m/s - 3 m/s divided by 8 s - 0s
a= 2 m/s / 8 m/s
a= 1/4 m/s^2

Answer 2

The acceleration is 0.4 m/s^2

Step-by-step explanation:

The acceleration is given by the change of rate of the velocity in a range of time, so:

`a=(vf-vo)/(t)\\where:\\vf=final\_velocity\\vo=initial\_velocity\\t=time`

`a=(6m/s-3m/s)/(8s)=0.4m/s^2`