Question

Please help! Trapezoid ABCD is composed of two right triangles and a rectangle. Find the area of trapezoid ABCD.

A: 336m2
B: 504m2
C:282m2
D:252m2

Answer 1

D

Find the area of the smaller triangle first.

Area of smaller triangle = 1/2 x 5 x 12 = 30 cm²

The bigger triangle and rectangle make up a trapezium.

Find the length of trapezium.

28 - 5 = 23 cm

Area of trapezium is given as 1/2 x sum of parallel sides x height.

Area of trapezium = 1/2 x (23+14) x 12 = 222 cm²

Area of trapezoid = 30 + 222 = 252 cm²

Answer 2

`252m^(2)`

Explanation:

The area of a trapezoid is
`(a+b)/(2) *h`

Where:

`a` and
`b` are the length of parallel sides

`h` is the height

So in this question:

`a` is 14

`b` is 28

`h` is 12

Plug in the values:

`(14+28)/(2) * 12`

`(42)/(2) *12`

`21 * 12`

`252`
`m^(2)`