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A weather plane took to the skies to measure the speed of the jet stream. The plane flew 1920 km with the jet stream as a tail wind. Then, it returned to its original location. The eastbound flight took 2 hours, and the westbound flight took 3.2 hours. Which system of equations can be used to find the speed of the jet stream and the speed of the plane? What was the speed of the jet stream? (p = plane, w = wind)

User Tom Carver
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Answer:

The correct answer is (A) p+w=960;p-w=600;jet streams speed=180km/h

Explanation:

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User Dravidian
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p = 780 w = 180 You didn't provide a list of equations to select from, so let's see about creating them and solving. For this I'll use the variable p for the airspeed of the jet and w for the speed of the wind in the jet stream. So when the jet is traveling in the same direction as the jet stream, the ground speed is p+w and when the jet is traveling in the opposite direction, the ground speed is p-w. With that in mind, we can create two equations and solve them. The equations are: (1). 1920 = 2(p+w) (2). 1920 = 3.2(p-w) Let's take equation (1) above and distribute the 2. 1920 = 2(p+w) (3) 1920 = 2p + 2w And do the same for equation (2) above. 1920 = 3.2(p-w) (4) 1920 = 3.2p - 3.2w Let's multiply (3) above by 1.6 to make the w terms equal in magnitude and opposite in sign to that in equation (4) above. 1920 = 2p + 2w (5) 3072 = 3.2p + 3.2w Add (4) and (5) above together, then solve for p (4) 1920 = 3.2p - 3.2w (5) 3072 = 3.2p + 3.2w 4992 = 6.4p 780 = p So the Jet's speed is 780 km/h Now use the speed of the Jet and (1) above to get the wind speed. 1920 = 2(p+w) 1920 = 2(780+w) 960 = 780 + w 180 = w So the wind speed is 180.