Question

The molar mass of a certain gas is 49 g. what is the density of the gas in g/l at stp?

Answer 1

The density of the gas is 49 times two which is 10

Answer 2

Answer : The density of gas at STP is, 2.19 g/L

Explanation :

To calculate the density of gas we are using ideal gas equation:

`PV=nRT\\\\PV=(w)/(M)RT\\\\P=(w)/(V)* (RT)/(M)\\\\P=(\rho RT)/(M)`

where,

P = pressure of gas = 1 atm (at STP)

T = temperature of gas = 273 K (at STP)

R = gas constant = 0.0821 L.atm/mole.K

M = molar mass of gas = 49 g/mole

Now put all the given values in the ideal gas equation, we get:

`1atm=(\rho * 0.0821L.atm/mole.K* 273K)/(49g/mol)`

`\rho=2.19g/L`

Therefore, the density of gas at STP is, 2.19 g/L