Question

2x2+4x-5=0 using quadratic formula

Answer 1

So solve for x? using the quadratic formula.
a = 2, b = 4, c = -5

x = (-b +/-
`\sqrt{b^(2)-4ac }`)/2a
= (-4 +/-
`√(16-4(2)(-5))`)/2(2)
= (-4 +/-
`√(16+40)`)/4
= (-4 +/- 2
`√(14)`)/4
= (-4 +/- 2
`√(14)`)/4
= -1 +/-
`√(14)`/2