Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = x = x = x = x =

Answer 1

x²+5x+5 has zeroes given by x=(-5±√25-20)/2=(-5±√5)/2=-1.3820 and -3.6180.
In simplest radical form the zeroes are -5/2+√5/2 and -5/2-√5/2.

Answer 2

`x=(-5\pm√(5))/(2)`

Explanation:

We have been given a function
`f(x)=x^2+5x+5`. We are asked to find the zeros of our given function.

We will use quadratic formula to solve our given problem.

`x=(-b\pm√(b^2-4ac))/(2a)`

Upon substituting our given values in above formula we will get,

`x=(-5\pm√(5^2-4*1*5))/(2*1)`

`x=(-5\pm√(25-20))/(2)`

`x=(-5\pm√(5))/(2)`

Therefore, the value of x is
`(-5\pm√(5))/(2)`.