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6, -12, 24, 8th term of geometric sequence

User GPX
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1 Answer

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17 votes

Answer:

a₈ = - 768

Explanation:

The nth term of a geometric sequence is


a_(n) = a₁
(r)^(n-1)

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r =
(a_(2) )/(a_(1) ) =
(-12)/(6) = - 2 , then

a₈ = 6 ×
-2)^(7) = - 6 × - 128 = - 768

User Rockney
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