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Find the zeros of g(x)=2x^2+32
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7 votes
Find the zeros of g(x)=2x^2+32

User Kikea
by
5.2k points

1 Answer

7 votes

Answer:

x = 4i, − 4i

Explanation:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x

x = 4i, − 4i

User SimonPJ
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5.3k points
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