Question

A chemist needs 1.36 mol of strontium bromide, SrBr2, for a reaction. What mass of strontium chloride should the chemist use?

Answer 1

mass SrBr2 = 247.42 g/mol x 1.36 mol
= 336 g

Answer 2

Answer: 336.5 grams

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

convert given masses into moles.

Number of Moles =
`\frac{\text{ given mass}}{\text{ molar mass}}`

Given number of moles = 1.36

Molar mass of
`SrBr_2` = 247.43 g/mol

Putting in the values we get

`1.36=\frac{\text {given mass}}{247.43g/mole}`

`{\text {given mass}}=336.5grams`

Thus mass of strontium bromide used should be 336.5 grams.