A chemist needs 1.36 mol of strontium bromide, SrBr2, for a reaction. What mass of strontium chloride should the chemist use?

Question

asked May 25, 2019 125k views

2 Answers

MichelleJS · Answer 1 · 2019-05-30T08:23:18+0000

Answer: 336.5 grams

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
6.023* 10^(23) of particles.

convert given masses into moles.

Number of Moles =
$\frac{\text{ given mass}}{\text{ molar mass}}$

Given number of moles = 1.36

Molar mass of
SrBr_2 = 247.43 g/mol

Putting in the values we get

$1.36=\frac{\text {given mass}}{247.43g/mole}$

${\text {given mass}}=336.5grams$

Thus mass of strontium bromide used should be 336.5 grams.