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What will the ball’s speed be in m/s when it reaches a height of 63 meters off the ground?

What will the ball’s speed be in m/s when it reaches a height of 63 meters off the-example-1
User Evan VanderZee
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1 Answer

11 votes
11 votes

Answer:

88.12 m/s

Step-by-step explanation:

The velocity-time-displacement equation is given by

v² = u² + 2ad

where
d = displacement

u = initial velocity

a = acceleration

v = final velocity

Plugging in known values for

u = 95 m/s,

a = -10 m/s² (acceleration is negative because it is in the opposite direction to gravity)

d = 63 m

We get
v² = 95² + 2 (-10) (63)

v² = 9025 - 1,260

v² = 7765

So v = √7765

v = 88.119 m/s = 88.12 m/s

User Alban Dericbourg
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