Answer:
9 Times
Step-by-step explanation:
The stopping distance of a car (or any traveling object) is proportional to the square of the speed of the car.
This is a consequence of the work-kinetic energy theorem, which states that the work done on the car is equal to its loss of kinetic energy:
![W=K_i-K_f](https://img.qammunity.org/2019/formulas/physics/high-school/1i0e92nph06p9fq4898ihpq1gegfcwj3p5.png)
Since the final speed of the car is zero, its final kinetic energy, so we can write:
![W=K_i\\Fd=(1)/(2)mv^2](https://img.qammunity.org/2019/formulas/physics/high-school/bg8n77yti8i7iqnsxw800o0uev9aa148uk.png)
where
F is the force that stops the car (the force of friction)
d is the stopping distance
m is the mass of the car
v is the initial speed of the car
As we see from the equation, the stopping distance (d) depends on the square of the speed (
). Therefore, it the speed is tripled, the stopping distance will acquire a factor
, so we will need 9 times the distance to stop.