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(-2i)(5i)(-1) how do you solve by simplifying showing the steps

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i = √(-1)

This is the fundamental property of i that you'll need to keep in mind when solving any problem with imaginary numbers (5i, 2i, 18i, etc.) or complex numbers (3+2i, 8-5i, etc). Squaring both sides of this definition, we also get that


i^2=-1

Which we can use to solve this problem. We have:


(-2i)(5i)(-1)\\ =(-10i^2)(-1)\\ =(-10)(-1)(-1)\\ =-10
User EternallyCurious
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