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How to factor z^12 - 64 (question 17.)
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Feb 27, 2019
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How to factor z^12 - 64 (question 17.)
Mathematics
high-school
Morleyc
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(z^6 - 8)(z^6 + 8) is the answer. If you verify this by multiplying, you will see that: (z^6 - 8)(z^6 + 8) = z^(6+6) + 8z^6 - 8z^6 - 64 = z^12 + 0 - 64 = z^12 - 64 Hope this helps, Brian
DivineTraube
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Mar 3, 2019
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