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What is the equation of a line that passes through the point (3,6) and (8,4)
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What is the equation of a line that passes through the point (3,6) and (8,4)

User Dmitry Sokolov
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1 Answer

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m=y2-y1/x2-x1
m=4-6/8-3=-2/5
y-y1=m(x-x1)
y-6=-2/5(x-3)
y-6=-2/5x+6/5
y=-2/5x+36/5
User Pouryak
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5.6k points
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