159k views
0 votes
Using the side lengths of pqr and stu which angle has a sine ratio of 4/5

Using the side lengths of pqr and stu which angle has a sine ratio of 4/5-example-1
User Keva
by
6.0k points

2 Answers

3 votes
sin = Opp/Hypo
so
sin P = 16/20 = 4/5
User QiAlex
by
5.8k points
4 votes

Answer:


sin P=(4)/(5).

Explanation:

In triangle QRP

PQ= 20

PR=12

QR= 16


sin\theta= (perpendicular\; side )/(Hypotenuse)


sinP=(QR)/(PQ)


\therefore sinP=(16)/(20)


sinP=(4)/(5)

sinQ=
(PR)/(PQ)

sinQ=
(12)/(20)

sinQ=
( 3)/(5)

In triangle STU

SU=16

UT=34

ST=30

sinU=
(ST)/(TU)

sinU=
(30)/(34)

sinU=
\frac { 15}{17}

sinT=
(US)/(UT)

sinT=
(16)/(34)

sinT=
\frac {8}{17}

Hence, sinP=
(4)/(5).

User Midhunhk
by
6.3k points