Question

Let g(x)=2x and h(x)=x^2+4 find the value (goh)(0)

Answer 1

(goh)=g(h(x))
h(0)=0^2+4=4
g(4)=8
(goh)(0)=8

Answer 2

ANSWER


`(g \circ \: h)(0) = 8`

Step-by-step explanation

The given function


`g(x) = 2x`

`h(x) = {x}^(2) + 4`

We want to find the composition of the function,


`(g \circ \: h)(x) = g(h(x))`


`(g \circ \: h)(x) = 2({x}^(2) + 4)`


`(g \circ \: h)(x) = 2{x}^(2) + 8`

We substitute


`x = 0`

to obtain,


`(g \circ \: h)(0) = 2({0})^(2) + 8`

This will simplify to,


`(g \circ \: h)(0) = 8`