Given :
A 1200 kg car initially traveling at 20 m/s increases its speed to 28m/s.
To Find :
How much work did the cars engine have to do to cause this change.
Solution :
We know, work done is given by :
Work Done = Final Kinetic Energy - Initial Kinetic Energy
![Work \ Done = (mv_f^2)/(2) - (mv_i^2)/(2)\\\\Work \ Done = (1200 * 28^2)/(2) - (1200* 20^2)/(2)\\\\Work \ Done = 230400\ J\\\\Work \ Done = 230.4 \ kJ](https://img.qammunity.org/2022/formulas/physics/high-school/dc42p63p6dcbr0t1o5bqz4tx5fm9pk80x3.png)
Therefore, work done by car engine is 230.4 kJ.