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The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint o. determine the magnitude r of the resultant r of the two forces and the angle θ which r makes with the positive x axis (measured counterclockwise from the x axis).

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we're going to remedy it with the parallelogram law.

\alpha = one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN

sin
\beta/3 = sin(eighty)/three.304 = 63.4 stages

3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4
User Julio
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