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A ball is rolled twice across the same level laboratory table and allowed to roll off the table and strike the floor. In each trial, the time it takes the ball to travel from the edge of the table to the floor is accurately measured. [Neglect friction.]

In trial B, the ball is traveling at 5.00 meters per second when it reaches the edge of the table. Compare the time it took the ball to reach the floor in trial B to the time it took the ball to reach the floor in trial A

User Gdubs
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Final answer:

The time it took the ball to reach the floor in trial B will be the same as the time it took for the ball to reach the floor in trial A.

Step-by-step explanation:

In trial B, the ball is traveling at a speed of 5.00 meters per second when it reaches the edge of the table. The time it took the ball to reach the floor in trial A will be the same as the time it took for the ball to reach the floor in trial B. This is because the time it takes for an object to fall only depends on its vertical motion, not its horizontal motion. Neglecting friction, the ball will take the same amount of time to fall to the floor in both trials.

User Dsuess
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By definition we know that the distance is equal to the speed by time
d = v * t
Clearing the time we have
t = d / v
for conservation of energy. we have to for every attempt
mgh = (1/2) mv ^ 2
Clearing the speed
v = Root (2gh)
Then, substituting
t = d / v
t = h / (Root (2gh)
We conclude that the time is the same since it depends on the height of the table to the floor.
User Jeferson Tenorio
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