Solve for x algebraically: 68= 1/5 (20x + 50) + 2

asked Sep 21, 2019 205k views

2 votes

Solve for x algebraically:

68= 1/5 (20x + 50) + 2

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3 votes

Answer:

68 = (1/5)(20x + 50) + 2

(1/5)(20x + 50) = 66

20x + 50 = 330

2x + 5 = 33

2x = 28

x = 14

Nikhil George answered Sep 26, 2019

5.6k points

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