Solve the following system:
{2 x - 3 y = 8 | (equation 1)
{6 y - 2 x = -20 | (equation 2)
Add equation 1 to equation 2:
{2 x - 3 y = 8 | (equation 1)
{0 x+3 y = -12 | (equation 2)
Divide equation 2 by 3:
{2 x - 3 y = 8 | (equation 1)
{0 x+y = -4 | (equation 2)
Add 3 × (equation 2) to equation 1:
{2 x+0 y = -4 | (equation 1)
{0 x+y = -4 | (equation 2)
Divide equation 1 by 2:
{x+0 y = -2 | (equation 1)
{0 x+y = -4 | (equation 2)
Collect results:
Answer: {x = -2
{y = -4