Answer:
Zinc hydroxide, Zn(OH)₂ is the limiting reactant.
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H₂SO₄ + Zn(OH)₂ —> ZnSO₄ + 2H₂O
From the balanced equation above,
1 mole of H₂SO₄ reacted with 1 mole of Zn(OH)₂.
Finally, we shall determine the limiting reactant. This can be obtained as follow:
From the balanced equation above,
1 mole of H₂SO₄ reacted with 1 mole of Zn(OH)₂.
Therefore, 0.511 mole of H₂SO₄ will also react with 0.511 mole of Zn(OH)₂.
From the calculation made above, we can see that it will take a higher amount (i.e 0.511 mole) of Zn(OH)₂ than what was given (i.e 0.464 mole) to react completely with 0.511 mole of H₂SO₄.
Therefore, Zn(OH)₂ is the limiting reactant and H₂SO₄ is the excess reactant.