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Find the m∠CDE, if m∠BAC = 50° and ∠BCA is a right angle.

40°
50°
90°
180°

Find the m∠CDE, if m∠BAC = 50° and ∠BCA is a right angle. 40° 50° 90° 180°-example-1
User Idan E
by
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2 Answers

1 vote
The answer would be because if angle BAC= 50 degrees then angle DCE= 50 degrees. These triangles are the same. Each triangle has to equal 180 degrees. We know that this is a 90 degree triangle.
50, 90 is what we have so far and we need angle CDE. 50+90= 140
140+what=180
140+40=180 so the answer is
Angle CDE=40 degrees
User Igor B
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8.7k points
4 votes
< BAC = 50
< BCA = 90

interior angles of a triangle add up to 180

so < ABC = 180 - (90 + 50) = 180 - 140 = 40

and < ABC = < CDE.......so < CDE = 40 <===

User Andrei  Belokopytov
by
8.0k points

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