Question

He specific heat of water is 4.18 j/(g * °c) how much heat, in kilojoules, must be added to 250 g of water to increase the temperature of the water by 5.0°c? report your answer with 3 significant figures.

Answer 1

Q=McDeltaT
Q= 250g×4.18j/g°c×5.0°c
Q=5225 joules
To get the kilojoules now I will have to divide the joules by 1000.

`q = (5225)/(1000) = 5.225kj`