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How many grams of naoh are needed to prepare 250ml of 0.205 m naoh?

User Nfernandez
by
7.9k points

1 Answer

1 vote
Concentration

=

Moles of solute (moles)
Volume of solution (L)
Thus
Concentration
×
volume
=
moles of solute
0.205

m
o
l

L

1
×
0.250

L
=
Moles of solute
=
0.0513

m
o
l
, an answer in moles as required.
And thus
mass of NaOH

=

moles
×
molar mass
=
0.0513

m
o
l
×
40.0

g

m
o
l

1
=
2.05

g
User Adam Prescott
by
8.3k points