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Boyle’s law states that the volume of a gas varies inversely with applied pressure. A helium balloon has a volume of 22 cubic meters at sea level where the air pressure is 1 atmosphere. The balloon is released and rises to a point where the air pressure is only 0.8 atmosphere. What is the volume at this height in cubic meters?

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Answer:

Volume, V₂ = 27.5 m³

Explanation:

According to Boyle's law, the volume of a gas varies inversely with applied pressure.

i.e.
V\propto(1)/(P)

or
V_1P_1=V_2P_2

V₁ = 22 m³

P₁ = 1 atm

P₂ = 0.8 atm

We have to find V₂ as :


V_2=(V_1P_1)/(P_2)


V_2=(22\ m^3* 1\ atm)/(0.8\ atm)


V_2=27.5\ m^3

Hence, the volume at the height is 27.5 m³

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