Question

A chemist dissolves 613 mg of pure perchloric acid in enough water to make up 360 mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places.

Answer 1

pH = 1.771

Step-by-step explanation:

given data

weight = 613 mg

volume of solution = 360 mL

solution

we get here first molarity that is

molarity =
`(weight)/(molecular \ weight) * (1000)/(volume \ of\ solution)` .................1

put here value

molarity =
`(613)/(100.46) * (1000)/(360)`

molarity = 0.01694 M

and

pH = -log[0.01694]

pH = 1.771