x=3, y=3
Solve the following system:
{4 x + 2 y = 18 | (equation 1)
2 x + 3 y = 15 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x + 2 y = 18 | (equation 1)
0 x+2 y = 6 | (equation 2)
Divide equation 1 by 2:
{2 x + y = 9 | (equation 1)
0 x+2 y = 6 | (equation 2)
Divide equation 2 by 2:
{2 x + y = 9 | (equation 1)
0 x+y = 3 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 6 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 2:{x+0 y = 3 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:Answer: {x = 3
y = 3