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A sled of mass 28 kg slides across the ground with a friction force of 200.3 N. What is k between the sled and the ground?

User Hgoebl
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2 Answers

4 votes

Answer:

it is 0.73

Step-by-step explanation:

User Raberana
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k=Frictional Force/Normal Force
Normal force would be mg, since it's not on an incline.
Normal Force = 28 kg*9.8 m/s^2 = 274.4 N

200.3 N/274.4 N = 0.73
User Gauthier
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