Question

Suppose that, while lying on a beach near the equator watching the Sun set over a calm ocean. you start a stopwatch just as the top of the Sun disappears. You then stand, elevating your eyes by a height H=1.70 m, and stop the watch when the top of the Sun again disappears. If the elapsed time is t=11.1 s, what is the radius r of Earth?

Answer 1

R = 1.699 ×
`10^(4)`

Step-by-step explanation:

given data

height H = 1.70 m

time is t = 11.1 s

to find out

radius r of Earth

solution

we get here cosθ so

cos(θ) = R ÷ (R+1.70) ................1

here θ = 360 × 11.1 ÷ (24×60×60)

θ = 0.04625

so put here value in eq 1

cos(0.04625) = R ÷ (R+1.70)

so radius R will be

0.9999 = R ÷ (R+1.70)

1.6999 + 0.999 R = R

R = 1.699 ×
`10^(4)`