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(1)/(x - 10) / \frac{9x}{x {}^(2) - 9x - 10}
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(1)/(x - 10) / \frac{9x}{x {}^(2) - 9x - 10}

User Saeed Entezari
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1 Answer

3 votes
When dividing fractions, you can flip the second one over and multiple.


(1)/(x-10)×
(x^2-9x-10)/(9x)


((1)(x^2-9x-10))/((x-10)(9x)) = (x^2-9x-10)/(9x^2-90x)
User Parthik Gosar
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