Answer:
1.22 m/s
1.76 m/s
0
1.46 m/s
Step-by-step explanation:
*in the first part i have taken 26 m as in the part above it is mentioned distance is 26 m.
= Displacement of the first run = 26 m
= Displacement of the second run = 26 m
= Time taken on the first run = 20.7 s
= Time taken on the second run = 14.8 s
Velocity is given by

Average velocity of the first run is 1.22 m/s

Average velocity of the first run is 1.76 m/s
Displacement for the round trip is 0 as she started and ended at the same point so her average velocity for the round trip is 0 m/s.
Average speed is given by

The average speed for the round trip is 1.46 m/s.