Answer:
the centripetal acceleration of the puck is 27 m/s²
Step-by-step explanation:
Given;
radius of the circular path, r = 3.0 m
velocity of the puck in the circular motion, v = 9.0 m/s
The centripetal acceleration of the puck is calculated as;
![a_c = (v^2)/(r) \\\\a_c = ((9)^2)/(3) \\\\a_c = 27 \ m/s^2](https://img.qammunity.org/2022/formulas/physics/college/d6sdevc1nmkac1on7riwi56q7dvqaum6ib.png)
Therefore, the centripetal acceleration of the puck is 27 m/s²