Question

How many atoms of carbon are in 0.425 g of ibuprofen?

Answer 1

Step-by-step explanation:

It is known that the chemical formula of Ibuprofen is
`C_(13)H_(18)O_(2)`.

According to Avogadro, 1 mole of an atom contains
`6.022 * 10^(23)` atoms.

As molar mass of Ibuprofen is 206.29 g/mol. So, number of moles of ibuprofen will be calculated as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

=
`(0.425 g)/(206.29 g/mol)`

=
`2.06 * 10^(-3)` mol

Since. there are 13 atoms of carbon present in a molecule of ibuprofen. Hence, total atoms of carbon present in
`2.06 * 10^(-3)` mol of Ibuprofen will be as follows.

`2.06 * 10^(-3) mol * 13 * 6.022 * 10^(23)`

=
`0.161 * 10^(23)` atoms

Thus, we can conclude that there are
`0.161 * 10^(23)` atoms of carbon are in 0.425 g of ibuprofen.

Answer 2

Answer is: 1,6·10²².
Molecular formula of ibuprofen is C₁₃H₁₈O₂.
m(C₁₃H₁₈O₂) = 0,425 g.
n (C₁₃H₁₈O₂) = m(C₁₃H₁₈O₂) ÷ m(C₁₃H₁₈O₂)
n(C₁₃H₁₈O₂) = 0,425g ÷206,3 g/mol = 0,002mol.
n(C) : n(C₁₃H₁₈O₂) = 13 : 1
n(C) = 0,026 mol.
N(C) = n(C) · Na = 0,026 mol · 6·10²³ 1/mol = 1,6·10²².
Na - Avogadro number.