Question

Write the first 5 terms of the arithmetic sequence whose first term is 8 and whose common difference is -6.

Answer 1

The first 5 terms of the arithmetic sequence are 8, 2, -4, -10, and -16.

Step-by-step explanation:

An arithmetic sequence is a sequence of numbers in which the difference between any two consecutive terms is constant. In this case, the first term is 8 and the common difference is -6.

To find the first 5 terms, we can use the formula for the nth term of an arithmetic sequence: an = a1 + (n - 1)d, where an is the nth term, a1 is the first term, n is the position of the term, and d is the common difference.

Plugging in the values, we get:

1. a1 = 8
2. d = -6
3. a2 = 8 + (2 - 1)(-6) = 8 - 6 = 2
4. a3 = 8 + (3 - 1)(-6) = 8 - 12 = -4
5. a4 = 8 + (4 - 1)(-6) = 8 - 18 = -10
6. a5 = 8 + (5 - 1)(-6) = 8 - 24 = -16

Therefore, the first 5 terms of the arithmetic sequence are 8, 2, -4, -10, and -16.

Answer 2

the formula for arithmetic sequence is given by:
an=a+(n-1)d
where:
an=nth term
a=first term
n=number of terms
thus our first term will be:
a1=8
a2=8+(2-1)(-6)=2
a3=8+(3-1)(-6)=-4
a4=8+(4-1)(-6)=-10
a5=8+(5-1)(-6)=-16
a5=-16
thus the sequence will be:
8,2,-4,-10,-16...