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A hydraulic lift is made by sealing an ideal fluid inside a container with an input piston of cross-sectional area 0.004 m2, and an output piston of cross-sectional area 1.2 m2. The pistons can slide up or down without friction while keeping the fluid sealed inside. The maximum weight that can be lifted when a force of 60 N is applied to the input piston is:________

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Answer:

18000N

Step-by-step explanation:

Pressure applied on the input piston = pressure applied on the output

Fi/Ai = Fo/Ao

Substitute the given values in the formula

60/0.004 = Fo/1.2

Croa multiply

0.004Fo = 60(1.2)

0.004Fo = 72

Fo = 72/0.004

Fo = 18000N

Hence the maximum weight that can be lifted when a force of 60 N is applied to the input piston is 18000N

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