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A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction is 0.8, what is the weight of the box?

A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction is 0.8, what is the weight of the box?
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A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction is 0.8, what is the weight of the box?

User Mr Matrix
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9.6k points

1 Answer

5 votes
The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
Therefore, clearing the normal force we have:
The friction is 565N.
(565 / 0.8) = 706.25N. weight.
User Jiejing Zhang
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8.4k points
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