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A rightward force of 246 N is applied to a 35 N suitcase to accelerate it across the floor. The coefficient of friction between the crate and the floor is 0.75. What is the acceleration of the crate?
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A rightward force of 246 N is applied to a 35 N suitcase to accelerate it across the floor. The coefficient of friction between the crate and the floor is 0.75. What is the acceleration of the crate?

User Chris Disley
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1 Answer

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(35/g) = mass of 3.57kg. (9.8 for g).
(35 x 0.75) = 26.25N. friction.
(246 - 26.25) = net 219.76N. accelerating force.
 Aceleration = (f/m) = (219.76/3.57) = 61.56m/sec^2
User Kaushik Burkule
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