Question

How many molecules of glucose, C6H12O6, can be “burned” biologically when 283.2 grams of oxygen is a available?

Answer 1

Answer is: 8,85·10²³ molecules of glucose.
Chemical reaction: C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.
m(C₆H₁₂O₆) =?
m(O₂) = 283,2 g.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 83,2 g ÷ 32 g/mol.
n(O₂) = 8,85 mol.
from reaction: n(O₂) : n(C₆H₁₂O₆) = 6 : 1.
n(C₆H₁₂O₆) = 1,475 mol.
N(C₆H₁₂O₆) = n · Na
N(C₆H₁₂O₆) = 1,475 mol · 6·10²³ 1/mol = 8,85·10²³.
Na - Avogadro number.