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you load an arrow into a bow and pull the bowstring back .50m. The bow has a spring constant k=2000N/m. What is the potential energy of the bowstring?

User Alex Kombo
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1 Answer

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potential energy = 1/2(spring constant)(distance from equilibrium)2

= > U = 1/2 * 2000 * 50 * 50

=> U = 2500000 Joules
User MissingLinq
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