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What is the range of f(x)=2x squared-2x+5 if the domain is (-2, -1, 0, 1, 2)?

User Kenial
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1 Answer

1 vote
plug in the 5 values in the domain

f(-2) = 2(-2)^2 - 2(-2) + 5 = 8+4+5 = 17 so first number in the range is 17.
f(-1) = 2(-1)^2 -2(-1) + 5 = 2 + 2 + 5 = 9
f(0) = 0 - 2 + 5 = 5
fond f(1) and f(2) in the same way

results are 17,9,5,5,9

so the range is {5, 9,17} (you don't repeat values)
User Elcomendante
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