Question

An ideal gas occupies a volume of 2.70 l at 2.80 atm and 28°c. if the temperature is raised to 36°c and the pressure is decreased to 1.30 atm, what is the final volume of the gas?

Answer 1

It is already stated in the given that the gas is ideal such that it will follow through the equation,

PV = nRT

If all else are equal except for the temperature and pressure, the equation that relates the initial and final conditions.

P₁V₁/T₁ = P₂V₂/T₂

Substituting the known values,

(2.80 atm)(2.70 L)/(28 + 273.15) = (1.30 atm)(V₂)/(36 + 273.15)

The value of V₂ is 5.97 L.

Answer: 5.97 L