Question

The perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the length is 90 yards more than the​ width?

Answer 1

P = 700 = 2l + 2w and l = w + 90

700 = 2(w+90) + 2w
700 = 2w + 2w + 180
700 - 180 = 4w
520 = 4w
w = 520 : 4
w = 130 yards
l = 130 + 90
l = 220

Answer 2

Use system of equations. We know l=w+90 and 2w+2l=700. Substitute w+90 in for l and solve.

l=220
w=130