Question

The artificial sweetener aspartame (nutra-sweet) formula c14h18n2o5 is used to sweeten diet foods, coffee and soft drinks. how many moles of aspartame are present in 225 g of aspartame?

Answer 1

Answer is: 0,765 moles of aspartame.
m(C₁₄H₁₈N₂O₅) = 225 g.
M(C₁₄H₁₈N₂O₅) = 14·12 + 18·1 + 2·14 + 5·16 = 294 g/mol.
n(C₁₄H₁₈N₂O₅) = m(C₁₄H₁₈N₂O₅) ÷ M(C₁₄H₁₈N₂O₅) = 225 g ÷ 294 g/mol.
n(C₁₄H₁₈N₂O₅) = 0,765 mol.
m - mass of aspartame.
M - molar mass of aspartame.
n - amount of substance of aspartame.

Answer 2

0.765 moles.
Let's calculate the molar mass of aspartame by starting with looking up the atomic weights of the involved elements:
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight nitrogen = 14.0067
Atomic weight oxygen = 15.999
Molar mass aspartame = 14 * 12.0107 + 18 * 1.00794 + 2 * 14.0067 + 5 * 15.999 = 294.30112 g/mol
Moles aspartame = 225 g / 294.30112 g/mol = 0.764523084 mol
Rounding to 3 significant figures gives 0.765 moles.