Question

How Do I solve this system of equations?

5x+4y=-14
3x+6y=6

Answer 1

Steps:
(5x+4y=-14)*3
(3x+6y=6)*2

15x+12y=-42
(6x+12y=12)*-

15x+12y=-42
-6x-12y=-12
Now add

9x=-54
x=-6

NOW SUBSTITUTE

3(-6)+6Y= 6
-18+6y=-6
6y=12
y=2

The ordered pair is (-6,2)

Answer 2

3x = -6y + 6 becomes x = -2y + 2 and then you substitute in 5( -2y + 2) + 4y = -14

-10y + 10 + 4y = -14
-6y = -24
6y = 24
y = 4

And then you put y in x = -2(4) + 2 to find x
X = -8 + 2 = -6
x = -6


Then you try in both
5(-6) + 4(4) = - 14 -> -30 + 16 is -14 ✔️
3(-6) + 6(4) = 6 -> -18 + 24 is 6 ✔️