Question

Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0? u2 – 11u + 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) + 24 where u = (x2 – 1) u2 + 1 – 11u + 24 = 0 where u = (x2 – 1) (u2 – 1)2 – 11(u2 – 1) + 24 where u = (x2 – 1)

please answer quickly timed test

Answer 1

u2 – 11u + 24 = 0 where u = (x2 – 1) the first awnser, a.

Answer 2

we have

`(x^(2)-1)^(2)-11(x^(2)-1)+24=0` --------> equation

Let

`u=x^(2)-1`

substitute the value of u in the equation

`(u)^(2)-11(u)+24=0`

`u^(2)-11u+24=0`

therefore

the answer is the first option

`u^(2)-11u+24=0` where
`u=x^(2)-1`