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Find the lowest common denominator of p+3/p^2+7p+10 and p+5/p^2+5p+6

User Zayra
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2 Answers

1 vote
the answer would be known as (P+5) (P+2) (P+3)
User Hugo Yates
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7 votes

Answer: The lowest common denominator of the given fractions is
(p+2)(p+3)(p+5).

Step-by-step explanation: We are given to find the lowest common denominator of the following fractions :


F_1=(p+3)/(p^2+7p+10),\\\\\\F_2=(p+5)/(p^2+5p+6).

To find the lowest common denominator, we need to factorize the denominators of both the fractions and take the L.C.M. of them.

We have


F_1=(p+3)/(p^2+7p+10)=(p+3)/(p^2+5p+2p+10)=(p+3)/((p+2)(p+5)),\\\\\\F_2=(p+5)/(p^2+5p+6)=(p+5)/(p^2+3p+2p+6)=(p+5)/((p+2)(p+3)).

Now, the L.C.M. of the denominators is given by


L.C.M.\{(p+2)(p+5),(p+2)(p+3)\}=(p+2)(p+3)(p+5).

Thus, the lowest common denominator of the given fractions is
(p+2)(p+3)(p+5).

User Darxtar
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