Question

What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chemical equation below?

H2SO4 --> 2 H+ + SO42-

Answer 1

Answer: 0.002 M

Step-by-step explanation:

The balanced chemical equation for ionization of
`H_2SO_4` in water is:

`H_2SO_4\rightarrow 2H^++SO_4^(2-)`

According to stoichiometry :

1 mole of
`H_2SO_4` ionizes to give =2 mole of
`H^+` ions

0.001 mole of
`H_2SO_4` ionizes to give =
`(2)/(1)* 0.001=0.002` mole of
`H^+` ions

Thus
`H^+` of a solution of 0.001 M aqueous sulfuric acid is 0.002 M