Question

Two cylinders contain pistons that are connected by fluid in a hydraulic system. A force of 1,300 N is exerted on one piston with an area of 0.05 m2. What is the force exerted on the other piston that has an area of 0.08 m?​

Answer 1

In a hydraulic system, the force exerted on the other piston can be calculated using the equation Force2 = (Area2/Area1) × Force1. In this case, the force exerted on the other piston is 2,080 N.

Step-by-step explanation:

In a hydraulic system, the force exerted on the other piston can be calculated using the equation:

Force2 = (Area2/Area1) × Force1

Given that Area1 is 0.05 m2 and Force1 is 1,300 N, and Area2 is 0.08 m2, we can substitute these values into the equation to calculate the force exerted on the other piston:

Force2 = (0.08 / 0.05) × 1,300

Force2 = 2,080 N

Answer 2

Given :

Two cylinders contain pistons that are connected by fluid in a hydraulic system.

A force of 1,300 N is exerted on one piston with an area of 0.05 m².

To Find :

The force exerted on the other piston that has an area of 0.08 m.

Solution :

Since, force is exerted between two cylinder, it means pressure is constant.

So,

`P_1 = P_2\\\\(F_1)/(A_1) = (F_2)/(A_2)\\\\(1300\ N)/(0.05 \ m^2) = (F_2)/(0.08\ m^2)\\\\F_2 = (1300* 0.08)/(0.05)\ N\\\\F_2 = 2080\ N`

Hence, this is the required solution.